How to reach Spring's beanfactory with ZK?

asked 2006-07-13 09:42:37 +0800

admin
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Orignial message at:
https://sourceforge.net/forum/message.php?msg_id=3820138

By: nobody

Hi,

I tried to integrate ZK with Spring and therefore used the examples from the small talks. I included Spring's ContextLoaderListener in web.xml:

<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring*.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-
class>
</listener>

This works and my beans are found as seen in Tomcat's console:

org.springframework.web.context.support.XmlWebApplicationContext:92 - Bean factory for application context [Root WebApplicationContext]:
org.springframework.beans.factory.support.DefaultListableBeanFactory defining beans [userDao,dataSource,sessionFactory,hibernateTemplate,userManager,userService];
root of BeanFactory hierarchy

Now I implemented the ServiceLocator, which does the following to the the
context:

static {
ctx = new ClassPathXmlApplicationContext("spring-hibernate.xml");
}

This doesn't work for me because the spring-*.xml files are not within the class path (/WebRoot/WEB-INF) and I'm not sure how to change this. So I changed it to "**/spring-hibernate.xml" and the file seems to be found. But then I get the following:
NoSuchBeanDefinitionException: No bean named 'userManager' is defined

What worked for me in the old myfaces implementation was this:
ServletContext context
= (ServletContext)FacesContext.getCurrentInstance().getExternalContext().getCont
ext();
this.appContext
= WebApplicationContextUtils.getRequiredWebApplicationContext(context);

But I don't know how to do this with ZK because I don't get a valid ServletContext.
After that, getting the beanfactory should not be a problem.

Does anyone have a hint for me?

Regards,
Oliver.