if statement

james

20 Dec 2008 00:27:59 GMT

I think this is sad, but... I'm at a loss...
I am trying to do an if statement in a function and it's just not working.
I have a test.zul file and a test.zs file. in the zul file, I have this... <zscript src="test.zs" />
Ultimately what I want, is to have some variables that i want to change depending on what's selected in a listbox.
Then what's done in the function will vary depending on what the variable is.
But the if statement just isn't working.
some example code...

test.zul

<variables type="1" />
<zscript src="test.zs" />
<listbox id="LBtest" mold="select" rows="1">
    <listitem label="first" value="1"/>
    <listitem label="second" value="2"/>
    <listitem label="third" value="3"/>
    <attribute name="onSelect">
        self.setVariable("type", LBtest.getSelectedItem().getValue(), true);
    </attribute>
</listbox>
<button label="submit" onClick="submit()"/>

test.zul

void submit() {
    if (type == "1"){
    	alert("1");
    }
    if (type == "2"){
    	alert("2");
    }
    if (type == "3"){
    	alert("3");
    }
    if (type != null){
    	alert("null...  type == "+type);
    }
}

In the if statement, I have tried using single quotes, no quotes, and even assigning other variables with the values, and then referencing the various variables...
Ex:

self.setVariable("varA", 1, true);
if (Qtype == varA){
    alert("1");
}

I get a message saying "null... type == 1" (or 2 or 3, if that's what i have selected)
If I say ...
if (type != "3"){
(doing this with all of them, no quotes, single quotes and double quotes) then I get an alert.
I dont know how to reference these... the variable registers as no being null... but what is it?
Or my real question... how do check the variable against something...
How do I check to see if the variable type is equal to 1, 2 or 3 so that i can know what to do in my function?
Any and all help is greatly appreciated... Sorry for the long intro here, but I don't know how else to clearly ask my question...
thanks.

RyanWu

22 Dec 2008 00:39:05 GMT

I found a problem in your code

if (type == "1")

when you using JAVA
make sure you check you string by using "String.equals(...)" not "=="

james

22 Dec 2008 19:12:49 GMT

Great, thank you very much.

ZK - Open Source Ajax Java Framework

if statement